{"id":6744,"date":"2021-10-21T13:38:11","date_gmt":"2021-10-21T08:08:11","guid":{"rendered":"https:\/\/mathemerize.com\/?p=6744"},"modified":"2021-10-25T02:03:51","modified_gmt":"2021-10-24T20:33:51","slug":"a-coin-is-tossed-successively-three-times-find-the-probability-of-getting-exactly-one-head-or-two-heads","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/a-coin-is-tossed-successively-three-times-find-the-probability-of-getting-exactly-one-head-or-two-heads\/","title":{"rendered":"A coin is tossed successively three times. Find the probability of getting exactly one head or two heads."},"content":{"rendered":"
We know that probability of event = no. of favorable outcome\/total outcome<\/p>\n
Sample space of event : { (H , H , H) , (H , H , T) , (H , T , H) , (H , T , T) , (T , H , H) , (T , H , T) , (T , T , H) , (T , T , T) }<\/p>\n
favorable outcome of getting one head : { (H , T , T) , (T , H , T) , (T , T , H) }<\/p>\n
Probability of getting one head = 3\/8<\/p>\n
favorable outcome of getting two head : { (H , H , T) , (H , T , H) , (T , H , H) }<\/p>\n
Probability of getting two head = 3\/8<\/p>\n
Probability of getting exactly one head or two heads = \\(3\\over 8\\) + \\(3\\over 8\\) = \\(6\\over 8\\) = \\(3\\over 4\\)<\/p>\n
Hence, Probability of getting exactly one head or two heads = \\(3\\over 4\\)<\/p>\n
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