{"id":6767,"date":"2021-10-21T14:11:18","date_gmt":"2021-10-21T08:41:18","guid":{"rendered":"https:\/\/mathemerize.com\/?p=6767"},"modified":"2021-10-25T02:03:23","modified_gmt":"2021-10-24T20:33:23","slug":"find-the-number-of-ways-of-dividing-52-cards-among-4-players-equally-such-that-each-gets-exactly-one-ace","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/find-the-number-of-ways-of-dividing-52-cards-among-4-players-equally-such-that-each-gets-exactly-one-ace\/","title":{"rendered":"Find the number of ways of dividing 52 cards among 4 players equally such that each gets exactly one Ace."},"content":{"rendered":"

Solution :<\/h2>\n

Total number of ways of dividing 48 cards(Excluding 4 Aces) in 4 groups = \\(48!\\over (12!)^4 4!\\)<\/p>\n

Now, distribute exactly one Ace to each group of 12 cards. Total number of ways = \\(48!\\over (12!)^4 4!\\) \\(\\times\\) 4!<\/p>\n

Now, distribute these groups of cards among four players<\/p>\n

= \\(48!\\over (12!)^4 4!\\) \\(\\times\\) 4!4!<\/p>\n

= \\(48!\\over (12!)^4\\) \\(\\times\\) 4!<\/p>\n

\n

Similar Questions<\/h3>\n

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Solution : Total number of ways of dividing 48 cards(Excluding 4 Aces) in 4 groups = \\(48!\\over (12!)^4 4!\\) Now, distribute exactly one Ace to each group of 12 cards. Total number of ways = \\(48!\\over (12!)^4 4!\\) \\(\\times\\) 4! Now, distribute these groups of cards among four players = \\(48!\\over (12!)^4 4!\\) \\(\\times\\) 4!4! …<\/p>\n

Find the number of ways of dividing 52 cards among 4 players equally such that each gets exactly one Ace.<\/span> Read More »<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"default","ast-global-header-display":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"default","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":""},"categories":[43,44],"tags":[],"yoast_head":"\nFind the number of ways of dividing 52 cards among 4 players equally such that each gets exactly one Ace.<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/mathemerize.com\/find-the-number-of-ways-of-dividing-52-cards-among-4-players-equally-such-that-each-gets-exactly-one-ace\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Find the number of ways of dividing 52 cards among 4 players equally such that each gets exactly one Ace.\" \/>\n<meta property=\"og:description\" content=\"Solution : Total number of ways of dividing 48 cards(Excluding 4 Aces) in 4 groups = (48!over (12!)^4 4!) 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