{"id":6771,"date":"2021-10-21T15:28:34","date_gmt":"2021-10-21T09:58:34","guid":{"rendered":"https:\/\/mathemerize.com\/?p=6771"},"modified":"2021-10-25T01:33:37","modified_gmt":"2021-10-24T20:03:37","slug":"in-how-many-ways-can-5-different-mangoes-4-different-oranges-3-different-apples-be-distributed-among-3-children-such-that-each-gets-atleast-one-mango","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/in-how-many-ways-can-5-different-mangoes-4-different-oranges-3-different-apples-be-distributed-among-3-children-such-that-each-gets-atleast-one-mango\/","title":{"rendered":"In how many ways can 5 different mangoes, 4 different oranges & 3 different apples be distributed among 3 children such that each gets atleast one mango?"},"content":{"rendered":"

Solution :<\/h2>\n

5 different mangoes can be distributed by following ways among 3 children such that each gets at least 1 :<\/p>\n

Total number of ways : (\\(5!\\over 3!1!1!2!\\) + \\(5!\\over 2!2!2!\\)) \\(\\times\\) 3!<\/p>\n

Now, the number of ways of distributing remaining fruits (i.e. 4 oranges + 3 apples) among 3 children = \\(3^7\\) (as each fruit has 3 options).<\/p>\n

Therefore, Total number of ways = (\\(5!\\over 3!2!\\) + \\(5!\\over {(2!)}^3\\)) \\(\\times\\) 3! \\(\\times\\) \\(3^7\\)<\/p>\n


\n

Similar Questions<\/h3>\n

How many different words can be formed by jumbling the letters in the word \u2018MISSISSIPPI\u2019 in which no two S are adjacent ?<\/a><\/p>\n

From 6 different novels and 3 different dictionaries, 4 novels and 1 dictionary are to be selected and arranged in a row on the shelf so that the dictionary is always in the middle. Then, the number of such arrangements is<\/a><\/p>\n

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The set S = {1,2,3,\u2026..,12} is to be partitioned into three sets A, B and C of equal size. Thus, \\(A\\cup B\\cup C\\) = S \\(A\\cap B\\) = \\(B\\cap C\\) = \\(A\\cap C\\) = \\(\\phi\\) The number of ways to partition S is<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"

Solution : 5 different mangoes can be distributed by following ways among 3 children such that each gets at least 1 : Total number of ways : (\\(5!\\over 3!1!1!2!\\) + \\(5!\\over 2!2!2!\\)) \\(\\times\\) 3! Now, the number of ways of distributing remaining fruits (i.e. 4 oranges + 3 apples) among 3 children = \\(3^7\\) (as …<\/p>\n

In how many ways can 5 different mangoes, 4 different oranges & 3 different apples be distributed among 3 children such that each gets atleast one mango?<\/span> Read More »<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"default","ast-global-header-display":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"default","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":""},"categories":[43,47],"tags":[],"yoast_head":"\nIn how many ways can 5 different mangoes, 4 different oranges & 3 different apples be distributed among 3 children such that each gets atleast one mango?<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/mathemerize.com\/in-how-many-ways-can-5-different-mangoes-4-different-oranges-3-different-apples-be-distributed-among-3-children-such-that-each-gets-atleast-one-mango\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"In how many ways can 5 different mangoes, 4 different oranges & 3 different apples be distributed among 3 children such that each gets atleast one mango?\" \/>\n<meta property=\"og:description\" content=\"Solution : 5 different mangoes can be distributed by following ways among 3 children such that each gets at least 1 : Total number of ways : ((5!over 3!1!1!2!) + (5!over 2!2!2!)) 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