{"id":6782,"date":"2021-10-21T16:42:59","date_gmt":"2021-10-21T11:12:59","guid":{"rendered":"https:\/\/mathemerize.com\/?p=6782"},"modified":"2021-10-23T17:12:06","modified_gmt":"2021-10-23T11:42:06","slug":"find-the-equation-of-ellipse-whose-foci-are-2-3-2-3-and-whose-semi-major-axis-is-of-length-sqrt5","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/find-the-equation-of-ellipse-whose-foci-are-2-3-2-3-and-whose-semi-major-axis-is-of-length-sqrt5\/","title":{"rendered":"Find the equation of ellipse whose foci are (2, 3), (-2, 3) and whose semi major axis is of length \\(\\sqrt{5}\\)."},"content":{"rendered":"
Here S = (2, 3) & S’ is (-2, 3) and b = \\(\\sqrt{5}\\) \\(\\implies\\) SS’ = 4 = 2ae \\(\\implies\\) ae = 2<\/p>\n
but \\(b^2\\) = \\(a^2(1-e^2)\\) \\(\\implies\\) 5 = \\(a^2\\) – 4 \\(\\implies\\) a = 3<\/p>\n
Hence the equation to major axis is y = 3.<\/p>\n
Centre of ellipse is midpoint of SS’ i.e. (0, 3)<\/p>\n
\\(\\therefore\\) Equation to ellipse is \\(x^2\\over a^2\\) + \\({(y-3)}^2\\over b^2\\) = 1 or \\(x^2\\over 9\\) + \\({(y-3)}^2\\over 5\\) = 1<\/p>\n
The foci of an ellipse are \\((\\pm 2, 0)\\) and its eccentricity is 1\/2, find its equation.<\/a><\/p>\n If the foci of a hyperbola are foci of the ellipse \\(x^2\\over 25\\) + \\(y^2\\over 9\\) = 1. If the eccentricity of the hyperbola be 2, then its equation is :<\/a><\/p>\n Find the equation of the ellipse whose axes are along the coordinate axes, vertices are \\((0, \\pm 10)\\) and eccentricity e = 4\/5.<\/a><\/p>\n Find the equation of the tangents to the ellipse \\(3x^2+4y^2\\) = 12 which are perpendicular to the line y + 2x = 4.<\/a><\/p>\n