{"id":6787,"date":"2021-10-21T16:47:53","date_gmt":"2021-10-21T11:17:53","guid":{"rendered":"https:\/\/mathemerize.com\/?p=6787"},"modified":"2021-10-23T17:06:42","modified_gmt":"2021-10-23T11:36:42","slug":"find-the-equation-of-the-tangents-to-the-ellipse-3x24y2-12-which-are-perpendicular-to-the-line-y-2x-4","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/find-the-equation-of-the-tangents-to-the-ellipse-3x24y2-12-which-are-perpendicular-to-the-line-y-2x-4\/","title":{"rendered":"Find the equation of the tangents to the ellipse \\(3x^2+4y^2\\) = 12 which are perpendicular to the line y + 2x = 4."},"content":{"rendered":"
Let m be the slope of the tangent, since the tangent is perpendicular to the line y + 2x = 4<\/p>\n
\\(\\therefore\\)\u00a0 mx – 2 = -1 \\(\\implies\\) m = \\(1\\over 2\\)<\/p>\n
Since \\(3x^2+4y^2\\) = 12 or \\(x^2\\over 4\\) + \\(y^2\\over 3\\) = 1<\/p>\n
Comparing this with \\(x^2\\over a^2\\) + \\(y^2\\over b^2\\) = 1<\/p>\n
\\(\\therefore\\) \\(a^2\\) = 4 and \\(b^2\\) = 3<\/p>\n
So the equation of the tangent are y = \\(1\\over 2\\)x \\(\\pm\\) \\(\\sqrt{4\\times {1\\over 4} + 3}\\)<\/p>\n
\\(\\implies\\) y = \\(1\\over 2\\)x \\(\\pm\\) 2 or x – 2y \\(\\pm\\) 4 = 0<\/p>\n
The foci of an ellipse are \\((\\pm 2, 0)\\) and its eccentricity is 1\/2, find its equation.<\/a><\/p>\n If the foci of a hyperbola are foci of the ellipse \\(x^2\\over 25\\) + \\(y^2\\over 9\\) = 1. If the eccentricity of the hyperbola be 2, then its equation is :<\/a><\/p>\n Find the equation of the ellipse whose axes are along the coordinate axes, vertices are \\((0, \\pm 10)\\) and eccentricity e = 4\/5.<\/a><\/p>\n For what value of k does the line y = x + k touches the ellipse \\(9x^2 + 16y^2\\) = 144.<\/a><\/p>\n