{"id":6854,"date":"2021-10-21T21:05:33","date_gmt":"2021-10-21T15:35:33","guid":{"rendered":"https:\/\/mathemerize.com\/?p=6854"},"modified":"2021-10-25T02:02:53","modified_gmt":"2021-10-24T20:32:53","slug":"a-bag-contains-4-red-and-4-blue-balls-four-balls-are-drawn-one-by-one-from-the-bag-then-find-the-probability-that-the-drawn-balls-are-in-alternate-color","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/a-bag-contains-4-red-and-4-blue-balls-four-balls-are-drawn-one-by-one-from-the-bag-then-find-the-probability-that-the-drawn-balls-are-in-alternate-color\/","title":{"rendered":"A bag contains 4 red and 4 blue balls. Four balls are drawn one by one from the bag, then find the probability that the drawn balls are in alternate color."},"content":{"rendered":"

Solution :<\/h2>\n

\\(E_1\\) : Event that first drawn ball is red, second is blue and so on.<\/p>\n

\\(E_2\\) : Event that first drawn ball is blue, second is red and so on.<\/p>\n

\\(\\therefore\\)\u00a0 P(\\(E_1\\)) = \\(4\\over 8\\) \\(\\times\\) \\(4\\over 7\\) \\(\\times\\) \\(3\\over 6\\) \\(\\times\\) \\(3\\over 5\\) and<\/p>\n

\\(\\therefore\\)\u00a0 P(\\(E_2\\)) = \\(4\\over 8\\) \\(\\times\\) \\(4\\over 7\\) \\(\\times\\) \\(3\\over 6\\) \\(\\times\\) \\(3\\over 5\\)<\/p>\n

P(E) = P(\\(E_1\\)) + P(\\(E_2\\)) = 2 \\(\\times\\) \\(4\\over 8\\) \\(\\times\\) \\(4\\over 7\\) \\(\\times\\) \\(3\\over 6\\) \\(\\times\\) \\(3\\over 5\\) = \\(6\\over 35\\)<\/p>\n

\n

Similar Questions<\/h3>\n

The probability of India winning a test match against the west indies is 1\/2 assuming independence from match to match. The probability that in a match series India\u2019s second win occurs at the third test is<\/a><\/p>\n

Three houses are available in a locality. Three persons apply for the houses. Each applies for one house without consulting others. The probability that three apply for the same house is<\/a><\/p>\n

Find the number of ways of dividing 52 cards among 4 players equally such that each gets exactly one Ace.<\/a><\/p>\n

A and B play a game, where each is asked to select a number from 1 to 25. If the two numbers match, both of them win a prize. The probability that they will not win a prize in a single trial is<\/a><\/p>\n

A die is thrown. Let A be the event that the number obtained is greater than 3. Let B be the event that the number obtained is less than 5. Then, \\(P(A \\cup B)\\) is<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"

Solution : \\(E_1\\) : Event that first drawn ball is red, second is blue and so on. \\(E_2\\) : Event that first drawn ball is blue, second is red and so on. \\(\\therefore\\)\u00a0 P(\\(E_1\\)) = \\(4\\over 8\\) \\(\\times\\) \\(4\\over 7\\) \\(\\times\\) \\(3\\over 6\\) \\(\\times\\) \\(3\\over 5\\) and \\(\\therefore\\)\u00a0 P(\\(E_2\\)) = \\(4\\over 8\\) \\(\\times\\) \\(4\\over 7\\) …<\/p>\n

A bag contains 4 red and 4 blue balls. Four balls are drawn one by one from the bag, then find the probability that the drawn balls are in alternate color.<\/span> Read More »<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"default","ast-global-header-display":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"default","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":""},"categories":[43,44],"tags":[],"yoast_head":"\nA bag contains 4 red and 4 blue balls. 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