{"id":6862,"date":"2021-10-21T21:14:58","date_gmt":"2021-10-21T15:44:58","guid":{"rendered":"https:\/\/mathemerize.com\/?p=6862"},"modified":"2021-10-25T02:33:13","modified_gmt":"2021-10-24T21:03:13","slug":"the-set-a-x-x-in-r-x2-16-and-2x-6-equal","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/the-set-a-x-x-in-r-x2-16-and-2x-6-equal\/","title":{"rendered":"The set A = [x : x \\(\\in\\) R, \\(x^2\\) = 16 and 2x = 6] equal"},"content":{"rendered":"
\\(x^2\\) = 16 \\(\\implies\\) x = \\(\\pm\\)4<\/p>\n
2x = 6 \\(\\implies\\) x = 3<\/p>\n
There is no value of x which satisfies both the above equations.<\/p>\n
Thus, A = \\(\\phi\\)<\/p>\n
If A = {x,y}, then the power set of A is<\/a><\/p>\n If aN = {ax : x \\(\\in\\) N}, then the set 6N \\(\\cap\\) 8N is equal to<\/a><\/p>\n Let A = [x: x \\(\\in\\) R, |x| < 1]; B = [x : x \\(\\in\\) R, |x – 1| \\(\\ge\\) 1] and A \\(\\cup\\) B = R – D, then the set D is<\/a><\/p>\n If A = {2, 4} and B = {3, 4, 5} then (A \\(\\cap\\) B) \\(\\times\\) (A \\(\\cup\\) B)<\/a><\/p>\n