{"id":6876,"date":"2021-10-21T21:37:20","date_gmt":"2021-10-21T16:07:20","guid":{"rendered":"https:\/\/mathemerize.com\/?p=6876"},"modified":"2021-10-25T09:35:03","modified_gmt":"2021-10-25T04:05:03","slug":"a-student-obtained-75-80-85-marks-in-three-subjects-if-the-marks-of-another-subject-are-added-then-his-average-marks-can-not-be-less-than","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/a-student-obtained-75-80-85-marks-in-three-subjects-if-the-marks-of-another-subject-are-added-then-his-average-marks-can-not-be-less-than\/","title":{"rendered":"A student obtained 75%, 80%, 85% marks in three subjects. If the marks of another subject are added then his average marks can not be less than"},"content":{"rendered":"
Total marks obtained from three subjects out of 300 = 75 + 80 + 85 = 240<\/p>\n
if the marks of another subject is added then the total marks obtained out of 400 is greater than 240<\/p>\n
if marks obtained in fourth subject is 0 then<\/p>\n
minimum average marks = \\(240\\over 400\\)\\(\\times\\)100 = 60%<\/p>\n
The mean and variance of a random variable X having a binomial distribution are 4 and 2 respectively, then P(X = 1) is<\/a><\/p>\n The median of a set of 9 distinct observations is 20.5. If each of the largest 4 observation of the set is increased by 2, then the median of the new is<\/a><\/p>\n The mean and the variance of a binomial distribution are 4 and 2, respectively. Then, the probability of 2 success is<\/a><\/p>\n In a series of 2n observations, half of them equals a and remaining half equal -a. If the standard deviation of the observation is 2, then |a| equal to<\/a><\/p>\n