{"id":6889,"date":"2021-10-21T22:05:33","date_gmt":"2021-10-21T16:35:33","guid":{"rendered":"https:\/\/mathemerize.com\/?p=6889"},"modified":"2021-10-25T09:56:46","modified_gmt":"2021-10-25T04:26:46","slug":"find-general-solution-of-2sinx-cosx1-cosx-sin2x","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/find-general-solution-of-2sinx-cosx1-cosx-sin2x\/","title":{"rendered":"Find general solution of (2sinx – cosx)(1 + cosx) = \\(sin^2x\\)"},"content":{"rendered":"
(2sinx – cosx)(1 + cosx) – (1 – \\(cos^2x\\)) = 0<\/p>\n
\\(\\therefore\\) (1 + cosx)(2sinx – cosx – 1 + cosx) = 0<\/p>\n
\\(\\therefore\\)\u00a0 (1 + cosx)(2sinx – 1) = 0<\/p>\n
\\(\\implies\\) cosx = -1\u00a0 or\u00a0 sinx = \\(1\\over 2\\)<\/p>\n
\\(\\implies\\)\u00a0 cosx = -1 = cos\\(\\pi\\)\u00a0 \\(\\implies\\)\u00a0 x = 2n\\(\\pi\\) + \\(\\pi\\) = (2n+1)\\(\\pi\\), n \\(\\in\\) I<\/p>\n
or\u00a0 sinx = \\(1\\over 2\\) = sin\\(\\pi\\over 6\\)\u00a0 \\(\\implies\\)\u00a0 x = k\\(\\pi + (-1)^k{\\pi\\over 6}\\), k \\(\\in\\) I<\/p>\n
If \\({1\\over 6}sin\\theta\\), \\(cos\\theta\\) and \\(tan\\theta\\) are in G.P. then the general solution for \\(\\theta\\) is<\/a><\/p>\n Solve : cos3x + sin2x \u2013 sin4x = 0<\/a><\/p>\n Solve : 6 \u2013 10cosx = 3\\(sin^2x\\)<\/a><\/p>\n