{"id":6924,"date":"2021-10-22T01:37:42","date_gmt":"2021-10-21T20:07:42","guid":{"rendered":"https:\/\/mathemerize.com\/?p=6924"},"modified":"2021-10-25T09:45:29","modified_gmt":"2021-10-25T04:15:29","slug":"the-x-coordinate-of-the-incenter-of-the-triangle-that-has-the-coordinates-of-mid-point-of-its-sides-as-01-11-and-10-is","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/the-x-coordinate-of-the-incenter-of-the-triangle-that-has-the-coordinates-of-mid-point-of-its-sides-as-01-11-and-10-is\/","title":{"rendered":"The x-coordinate of the incenter of the triangle that has the coordinates of mid-point of its sides as (0,1), (1,1) and (1,0) is"},"content":{"rendered":"
Given mid-points of a triangle are (0,1), (1,1) and (1,0).<\/p>\n
So, by distance formula sides of the triangle are 2, 2 and \\(2\\sqrt{2}\\).<\/p>\n
x-coordinate of the incenter = \\(2*0 + 2\\sqrt{2}*0 + 2*2\\over {2 + 2 + 2\\sqrt{2}}\\)<\/p>\n
= \\(2\\over {2+\\sqrt{2}}\\)<\/p>\n
Find the distance between the line 12x \u2013 5y + 9 = 0 and the point (2,1)<\/a><\/p>\n If the line 2x + y = k passes through the point which divides the line segment joining the points (1,1) and (2,4) in the ratio 3:2, then k is equal to<\/a><\/p>\n If p is the length of the perpendicular from the origin to the line \\(x\\over a\\) + \\(y\\over b\\) = 1, then prove that \\(1\\over p^2\\) = \\(1\\over a^2\\) + \\(1\\over b^2\\)<\/a><\/p>\n Let a, b, c and d be non-zero numbers. If the point of intersection of the lines 4ax+2ay+c=0 and 5bx+2by+d=0 lies in the fourth quadrant and is equidistant from the two axes, then<\/a><\/p>\n