{"id":6931,"date":"2021-10-22T01:41:16","date_gmt":"2021-10-21T20:11:16","guid":{"rendered":"https:\/\/mathemerize.com\/?p=6931"},"modified":"2021-10-25T02:29:47","modified_gmt":"2021-10-24T20:59:47","slug":"let-a-and-b-be-two-sets-containing-2-elements-and-4-elements-respectively-the-number-of-subsets-atimesb-having-3-or-more-elements-is","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/let-a-and-b-be-two-sets-containing-2-elements-and-4-elements-respectively-the-number-of-subsets-atimesb-having-3-or-more-elements-is\/","title":{"rendered":"Let A and B be two sets containing 2 elements and 4 elements, respectively. The number of subsets A\\(\\times\\)B having 3 or more elements is"},"content":{"rendered":"

Solution :<\/h2>\n

Given, n(A) = 2 and n(B) = 4<\/p>\n

\\(\\therefore\\) n(A\\(\\times\\)B) = 8<\/p>\n

The number of subsets of (A\\(times\\)B) having 3 or more elements = \\(^8C_3 + {^8C_4} + ….. + {^8C_8}\\)<\/p>\n

= \\(2^8 – {^8C_0} – {^8C_1} – {^8C_2}\\)<\/p>\n

= 256 – 1 – 8 – 28 = 219\u00a0 \u00a0 \u00a0[\\(\\because\\) \\(2^n\\) = \\(^nC_0\u00a0 + {^nC_1} + ….. + {^nC_n}\\)]<\/p>\n


\n

Similar Questions<\/h3>\n

If A = {x,y}, then the power set of A is<\/a><\/p>\n

If aN = {ax : x \\(\\in\\) N}, then the set 6N \\(\\cap\\) 8N is equal to<\/a><\/p>\n

Let A = [x: x \\(\\in\\) R, |x| < 1]; B = [x : x \\(\\in\\) R, |x – 1| \\(\\ge\\) 1] and A \\(\\cup\\) B = R – D, then the set D is<\/a><\/p>\n

The set A = [x : x \\(\\in\\) R, \\(x^2\\) = 16 and 2x = 6] equal<\/a><\/p>\n

If N is a set of first 10 natural numbers and a relation R is defined as a + 2b = 10 where a, b \\(\\in\\) N. find inverse of R.<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"

Solution : Given, n(A) = 2 and n(B) = 4 \\(\\therefore\\) n(A\\(\\times\\)B) = 8 The number of subsets of (A\\(times\\)B) having 3 or more elements = \\(^8C_3 + {^8C_4} + ….. + {^8C_8}\\) = \\(2^8 – {^8C_0} – {^8C_1} – {^8C_2}\\) = 256 – 1 – 8 – 28 = 219\u00a0 \u00a0 \u00a0[\\(\\because\\) \\(2^n\\) = …<\/p>\n

Let A and B be two sets containing 2 elements and 4 elements, respectively. The number of subsets A\\(\\times\\)B having 3 or more elements is<\/span> Read More »<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"default","ast-global-header-display":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"default","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":""},"categories":[43,56],"tags":[],"yoast_head":"\nLet A and B be two sets containing 2 elements and 4 elements, respectively. The number of subsets A\\(\\times\\)B having 3 or more elements is<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/mathemerize.com\/let-a-and-b-be-two-sets-containing-2-elements-and-4-elements-respectively-the-number-of-subsets-atimesb-having-3-or-more-elements-is\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Let A and B be two sets containing 2 elements and 4 elements, respectively. 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