{"id":6935,"date":"2021-10-22T01:45:40","date_gmt":"2021-10-21T20:15:40","guid":{"rendered":"https:\/\/mathemerize.com\/?p=6935"},"modified":"2021-10-25T01:29:41","modified_gmt":"2021-10-24T19:59:41","slug":"from-6-different-novels-and-3-different-dictionaries-4-novels-and-1-dictionary-are-to-be-selected-and-arranged-in-a-row-on-the-shelf-so-that-the-dictionary-is-always-in-the-middle-then-the-number-o","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/from-6-different-novels-and-3-different-dictionaries-4-novels-and-1-dictionary-are-to-be-selected-and-arranged-in-a-row-on-the-shelf-so-that-the-dictionary-is-always-in-the-middle-then-the-number-o\/","title":{"rendered":"From 6 different novels and 3 different dictionaries, 4 novels and 1 dictionary are to be selected and arranged in a row on the shelf so that the dictionary is always in the middle. Then, the number of such arrangements is"},"content":{"rendered":"

Solution :<\/h2>\n

The number of ways in which 4 novels can be selected = \\(^6C_4\\) = 15<\/p>\n

The number of ways in which 1 dictionary can be selected = \\(^3C_1\\) = 3<\/p>\n

Now, we have 5 places in which middle place is fixed.<\/p>\n

\\(\\therefore\\)\u00a0 4 novels can be arranged in 4! ways<\/p>\n

\\(\\therefore\\)\u00a0 total number of ways = 15 \\(\\times\\) 4! \\(\\times\\) 3<\/p>\n

= 15 \\(\\times\\) 24 \\(\\times\\) 3<\/p>\n

= 1080<\/p>\n


\n

Similar Questions<\/h3>\n

How many different words can be formed by jumbling the letters in the word \u2018MISSISSIPPI\u2019 in which no two S are adjacent ?<\/a><\/p>\n

How many numbers can be formed with the digits 1, 2, 3, 4, 3, 2, 1 so that the odd digits always occupy the odd places?<\/a><\/p>\n

There are 10 points in a plane, out of these 6 are collinear. If N is the number of triangles formed by joining these points, then<\/a><\/p>\n

Let \\(T_n\\) be the number of all possible triangles formed by joining vertices of an n-sided regular polygon. If \\(T_{n+1}\\) \u2013 \\(T_n\\) = 10, then the value of n is<\/a><\/p>\n

From a group of 10 persons consisting of 5 lawyers, 3 doctors and 2 engineers, four persons are selected at random. The probability that selection contains one of each category is<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"

Solution : The number of ways in which 4 novels can be selected = \\(^6C_4\\) = 15 The number of ways in which 1 dictionary can be selected = \\(^3C_1\\) = 3 Now, we have 5 places in which middle place is fixed. \\(\\therefore\\)\u00a0 4 novels can be arranged in 4! ways \\(\\therefore\\)\u00a0 total number …<\/p>\n

From 6 different novels and 3 different dictionaries, 4 novels and 1 dictionary are to be selected and arranged in a row on the shelf so that the dictionary is always in the middle. Then, the number of such arrangements is<\/span> Read More »<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"default","ast-global-header-display":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"default","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":""},"categories":[43,47],"tags":[],"yoast_head":"\nFrom 6 different novels and 3 different dictionaries, 4 novels and 1 dictionary are to be selected and arranged in a row on the shelf so that the dictionary is always in the middle. 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