{"id":6958,"date":"2021-10-22T02:06:50","date_gmt":"2021-10-21T20:36:50","guid":{"rendered":"https:\/\/mathemerize.com\/?p=6958"},"modified":"2021-10-23T17:13:25","modified_gmt":"2021-10-23T11:43:25","slug":"the-length-of-the-diameter-of-the-circle-which-touches-the-x-axis-at-the-point-10-and-passes-through-the-point-23-is","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/the-length-of-the-diameter-of-the-circle-which-touches-the-x-axis-at-the-point-10-and-passes-through-the-point-23-is\/","title":{"rendered":"The length of the diameter of the circle which touches the X-axis at the point (1,0) and passes through the point (2,3) is"},"content":{"rendered":"
Let us assume that the coordinates of the center of the circle are C(h,k) and its radius is r.<\/p>\n
Now, since the circle touches X-axis at (1,0), hence its radius should be equal to ordinate of center.<\/p>\n
\\(\\implies\\) r = k<\/p>\n
Hence, the equation of circle is \\((x – h)^2 + (y – k)^2\\) = \\(k^2\\)<\/p>\n
Also, given that the circle passes through points (1, 0) and (2, 3). Hence, substituting them, in the equation of circle we get<\/p>\n
\\((1 – h)^2 + (0 – k)^2\\) = \\(k^2\\)\u00a0 \u00a0 \u00a0 \u00a0……(i)<\/p>\n
\\((2 – h)^2 + (3 – k)^2\\) = \\(k^2\\)\u00a0 \u00a0 \u00a0 \u00a0 ……(ii)<\/p>\n
from equations (i) and (ii), we get<\/p>\n
k = \\(5\\over 3\\)<\/p>\n
Hence, The diameter of the circle is 2k = \\(10\\over 3\\)<\/p>\n
The equation of the circle passing through the foci of the ellipse \\(x^2\\over 16\\) + \\(y^2\\over 9\\) = 1 and having center at (0, 3) is<\/a><\/p>\n The circle passing through (1,-2) and touching the axis of x at (3, 0) also passes through the point ?<\/a><\/p>\n Let C be the circle with center at (1,1) and radius 1. If T is the circle centered at (0,y) passing through origin and touching the circle C externally, then the radius of T is equal to<\/a><\/p>\n The equation of the circle through the points of intersection of \\(x^2 + y^2 \u2013 1\\) = 0, \\(x^2 + y^2 \u2013 2x \u2013 4y + 1\\) = 0 and touching the line x + 2y = 0, is<\/a><\/p>\n