{"id":6971,"date":"2021-10-22T02:23:40","date_gmt":"2021-10-21T20:53:40","guid":{"rendered":"https:\/\/mathemerize.com\/?p=6971"},"modified":"2021-10-25T09:31:10","modified_gmt":"2021-10-25T04:01:10","slug":"if-the-mean-deviation-about-the-median-of-numbers-a-2a-50a-is-50-then-a-is-equal-to","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/if-the-mean-deviation-about-the-median-of-numbers-a-2a-50a-is-50-then-a-is-equal-to\/","title":{"rendered":"If the mean deviation about the median of numbers a, 2a, …. , 50a is 50, then |a| is equal to"},"content":{"rendered":"

Solution :<\/h2>\n

Median of a, 2a, 3a, 4a, ….. . 50a is<\/p>\n

\\(25a + 26a\\over 2\\) = 25.5a<\/p>\n

Mean deviation = \\(\\sum{|x_i – Median|}\\over N\\)<\/p>\n

\\(\\implies\\)\u00a0 50 = \\(1\\over 50\\) {2|a|.(0.5 + 1.5 + …… + 24.5)]<\/p>\n

\\(\\implies\\) 2500 = 2|a|. \\(25\\over 2\\) (25)<\/p>\n

\\(\\implies\\) |a| = 4<\/p>\n


\n

Similar Questions<\/h3>\n

The mean and variance of a random variable X having a binomial distribution are 4 and 2 respectively, then P(X = 1) is<\/a><\/p>\n

The median of a set of 9 distinct observations is 20.5. If each of the largest 4 observation of the set is increased by 2, then the median of the new is<\/a><\/p>\n

A student obtained 75%, 80%, 85% marks in three subjects. If the marks of another subject are added then his average marks can not be less than<\/a><\/p>\n

In a series of 2n observations, half of them equals a and remaining half equal -a. If the standard deviation of the observation is 2, then |a| equal to<\/a><\/p>\n

The variance of first 50 even natural numbers is<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"

Solution : Median of a, 2a, 3a, 4a, ….. . 50a is \\(25a + 26a\\over 2\\) = 25.5a Mean deviation = \\(\\sum{|x_i – Median|}\\over N\\) \\(\\implies\\)\u00a0 50 = \\(1\\over 50\\) {2|a|.(0.5 + 1.5 + …… + 24.5)] \\(\\implies\\) 2500 = 2|a|. \\(25\\over 2\\) (25) \\(\\implies\\) |a| = 4 Similar Questions The mean and variance of …<\/p>\n

If the mean deviation about the median of numbers a, 2a, …. , 50a is 50, then |a| is equal to<\/span> Read More »<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"default","ast-global-header-display":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"default","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":""},"categories":[43,58],"tags":[],"yoast_head":"\nIf the mean deviation about the median of numbers a, 2a, .... , 50a is 50, then |a| is equal to<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/mathemerize.com\/if-the-mean-deviation-about-the-median-of-numbers-a-2a-50a-is-50-then-a-is-equal-to\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"If the mean deviation about the median of numbers a, 2a, .... , 50a is 50, then |a| is equal to\" \/>\n<meta property=\"og:description\" content=\"Solution : Median of a, 2a, 3a, 4a, ….. . 50a is (25a + 26aover 2) = 25.5a Mean deviation = (sum{|x_i – Median|}over N) (implies)\u00a0 50 = (1over 50) {2|a|.(0.5 + 1.5 + …… + 24.5)] (implies) 2500 = 2|a|. 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