{"id":6973,"date":"2021-10-22T02:25:59","date_gmt":"2021-10-21T20:55:59","guid":{"rendered":"https:\/\/mathemerize.com\/?p=6973"},"modified":"2021-10-25T09:31:51","modified_gmt":"2021-10-25T04:01:51","slug":"a-scientist-is-weighing-each-of-30-fishes-their-mean-weight-worked-out-is-30-g-and-a-standard-deviation-of-2-g-later-it-was-found-that-the-measuring-scale-was-misaligned-and-always-under-reported-e","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/a-scientist-is-weighing-each-of-30-fishes-their-mean-weight-worked-out-is-30-g-and-a-standard-deviation-of-2-g-later-it-was-found-that-the-measuring-scale-was-misaligned-and-always-under-reported-e\/","title":{"rendered":"A scientist is weighing each of 30 fishes. Their mean weight worked out is 30 g and a standard deviation of 2 g. Later, it was found that the measuring scale was misaligned and always under reported every fish weight by 2 g. The correct mean and standard deviation in gram of fishes are respectively."},"content":{"rendered":"
Correct mean = old mean + 2 = 30 + 2 = 32<\/p>\n
As standard deviation is independent of change of origin.<\/p>\n
Hence, it remains same.<\/p>\n
The mean and variance of a random variable X having a binomial distribution are 4 and 2 respectively, then P(X = 1) is<\/a><\/p>\n The median of a set of 9 distinct observations is 20.5. If each of the largest 4 observation of the set is increased by 2, then the median of the new is<\/a><\/p>\n The mean and the variance of a binomial distribution are 4 and 2, respectively. Then, the probability of 2 success is<\/a><\/p>\n If mean of the series \\(x_1\\), \\(x^2\\), \u2026.. , \\(x_n\\) is \\(\\bar{x}\\), then the mean of the series \\(x_i\\) + 2i, i = 1, 2, \u2026\u2026, n will be<\/a><\/p>\n