{"id":6992,"date":"2021-10-22T14:29:52","date_gmt":"2021-10-22T08:59:52","guid":{"rendered":"https:\/\/mathemerize.com\/?p=6992"},"modified":"2021-10-25T09:22:54","modified_gmt":"2021-10-25T03:52:54","slug":"the-average-marks-of-boys-in-a-class-is-52-and-that-of-girls-is-42-the-average-marks-of-boys-and-girls-combined-is-50-the-percentage-of-boys-in-the-class-is","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/the-average-marks-of-boys-in-a-class-is-52-and-that-of-girls-is-42-the-average-marks-of-boys-and-girls-combined-is-50-the-percentage-of-boys-in-the-class-is\/","title":{"rendered":"The average marks of boys in a class is 52 and that of girls is 42. The average marks of boys and girls combined is 50. The percentage of boys in the class is"},"content":{"rendered":"

Solution :<\/h2>\n

Let the number of boys and girls be x and y, respectively<\/p>\n

\\(\\therefore\\)\u00a0 \u00a052x + 42y = 50(x + y)<\/p>\n

\\(\\implies\\)\u00a0 52x + 42y = 50x + 50y<\/p>\n

\\(\\implies\\)\u00a0 2x = 8y<\/p>\n

\\(\\implies\\)\u00a0 x = 4y<\/p>\n

\\(\\therefore\\)\u00a0 Total number of students in the class<\/p>\n

= x + y = 4y + y = 5y<\/p>\n

\\(\\therefore\\)\u00a0 Required number of boys<\/p>\n

= \\(4y\\over 5y\\) \\(\\times\\) 100% = 80%<\/p>\n

\n

Similar Questions<\/h3>\n

The mean and variance of a random variable X having a binomial distribution are 4 and 2 respectively, then P(X = 1) is<\/a><\/p>\n

The median of a set of 9 distinct observations is 20.5. If each of the largest 4 observation of the set is increased by 2, then the median of the new is<\/a><\/p>\n

The mean and the variance of a binomial distribution are 4 and 2, respectively. Then, the probability of 2 success is<\/a><\/p>\n

In a series of 2n observations, half of them equals a and remaining half equal -a. If the standard deviation of the observation is 2, then |a| equal to<\/a><\/p>\n

All the students of a class performed poorly in mathematics. The teacher decided to give grace marks of 10 to each of the students. Which statistical measure will not change even after the grace marks were given ?<\/a><\/p>\n\n\n

<\/p>\n","protected":false},"excerpt":{"rendered":"

Solution : Let the number of boys and girls be x and y, respectively \\(\\therefore\\)\u00a0 \u00a052x + 42y = 50(x + y) \\(\\implies\\)\u00a0 52x + 42y = 50x + 50y \\(\\implies\\)\u00a0 2x = 8y \\(\\implies\\)\u00a0 x = 4y \\(\\therefore\\)\u00a0 Total number of students in the class = x + y = 4y + y = …<\/p>\n

The average marks of boys in a class is 52 and that of girls is 42. The average marks of boys and girls combined is 50. The percentage of boys in the class is<\/span> Read More »<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"default","ast-global-header-display":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"default","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":""},"categories":[43,58],"tags":[],"yoast_head":"\nThe average marks of boys in a class is 52 and that of girls is 42. 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