{"id":7000,"date":"2021-10-22T14:38:29","date_gmt":"2021-10-22T09:08:29","guid":{"rendered":"https:\/\/mathemerize.com\/?p=7000"},"modified":"2021-10-25T09:21:17","modified_gmt":"2021-10-25T03:51:17","slug":"if-in-a-frequency-distribution-the-mean-and-median-are-21-and-22-respectively-then-its-mode-is-approximately","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/if-in-a-frequency-distribution-the-mean-and-median-are-21-and-22-respectively-then-its-mode-is-approximately\/","title":{"rendered":"If in a frequency distribution, the mean and median are 21 and 22 respectively, then its mode is approximately"},"content":{"rendered":"<h2>Solution :<\/h2>\n<p>Given that, mean = 21 and median = 22<\/p>\n<p>Using the relation,<\/p>\n<p>Mode\u00a0 = 3 median &#8211; 2 mean<\/p>\n<p>\\(\\implies\\) Mode = 3(22) &#8211; 2(21)<\/p>\n<p>= 66 &#8211; 42 = 24<\/p>\n<hr \/>\n<h3 style=\"text-align: center;\">Similar Questions<\/h3>\n<p><a class=\"row-title\" href=\"https:\/\/mathemerize.com\/the-mean-and-variance-of-a-random-variable-x-having-a-binomial-distribution-are-4-and-2-respectively-then-px-1-is\/\" aria-label=\"\u201cThe mean and variance of a random variable X having a binomial distribution are 4 and 2 respectively, then P(X = 1) is\u201d (Edit)\">The mean and variance of a random variable X having a binomial distribution are 4 and 2 respectively, then P(X = 1) is<\/a><\/p>\n<p><a class=\"row-title\" href=\"https:\/\/mathemerize.com\/find-the-variance-of-first-n-even-natural-numbers\/\" aria-label=\"\u201cFind the variance of first n even natural numbers ?\u201d (Edit)\">Find the variance of first n even natural numbers ?<\/a><\/p>\n<p><a class=\"row-title\" href=\"https:\/\/mathemerize.com\/the-mean-and-the-variance-of-a-binomial-distribution-are-4-and-2-respectively-then-the-probability-of-2-success-is\/\" aria-label=\"\u201cThe mean and the variance of a binomial distribution are 4 and 2, respectively. Then, the probability of 2 success is\u201d (Edit)\">The mean and the variance of a binomial distribution are 4 and 2, respectively. Then, the probability of 2 success is<\/a><\/p>\n<p><a class=\"row-title\" href=\"https:\/\/mathemerize.com\/in-a-series-of-2n-observations-half-of-them-equals-a-and-remaining-half-equal-a-if-the-standard-deviation-of-the-observation-is-2-then-a-equal-to\/\" aria-label=\"\u201cIn a series of 2n observations, half of them equals a and remaining half equal -a. If the standard deviation of the observation is 2, then |a| equal to\u201d (Edit)\">In a series of 2n observations, half of them equals a and remaining half equal -a. If the standard deviation of the observation is 2, then |a| equal to<\/a><\/p>\n<p><a class=\"row-title\" href=\"https:\/\/mathemerize.com\/the-mean-of-the-numbers-a-b-8-5-10-is-6-and-the-variance-is-6-80-then-find-the-values-of-a-and-b\/\" aria-label=\"\u201cThe mean of the numbers a, b, 8, 5, 10 is 6 and the variance is 6.80. Then, find the values of a and b?\u201d (Edit)\">The mean of the numbers a, b, 8, 5, 10 is 6 and the variance is 6.80. Then, find the values of a and b?<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Solution : Given that, mean = 21 and median = 22 Using the relation, Mode\u00a0 = 3 median &#8211; 2 mean \\(\\implies\\) Mode = 3(22) &#8211; 2(21) = 66 &#8211; 42 = 24 Similar Questions The mean and variance of a random variable X having a binomial distribution are 4 and 2 respectively, then P(X &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/mathemerize.com\/if-in-a-frequency-distribution-the-mean-and-median-are-21-and-22-respectively-then-its-mode-is-approximately\/\"> <span class=\"screen-reader-text\">If in a frequency distribution, the mean and median are 21 and 22 respectively, then its mode is approximately<\/span> Read More &raquo;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"default","ast-global-header-display":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"default","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":""},"categories":[43,58],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v20.12 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>If in a frequency distribution, the mean and median are 21 and 22 respectively, then its mode is approximately<\/title>\n<meta name=\"robots\" content=\"index, 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