{"id":7009,"date":"2021-10-22T14:44:50","date_gmt":"2021-10-22T09:14:50","guid":{"rendered":"https:\/\/mathemerize.com\/?p=7009"},"modified":"2021-10-25T01:46:57","modified_gmt":"2021-10-24T20:16:57","slug":"the-probability-that-a-speaks-truth-is-4-5-while-this-probability-for-b-is-3-4-the-probability-that-they-contradict-each-other-when-asked-to-speak-on-a-fact-is","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/the-probability-that-a-speaks-truth-is-4-5-while-this-probability-for-b-is-3-4-the-probability-that-they-contradict-each-other-when-asked-to-speak-on-a-fact-is\/","title":{"rendered":"The probability that A speaks truth is 4\/5 while this probability for B is 3\/4. The probability that they contradict each other when asked to speak on a fact is"},"content":{"rendered":"

Solution :<\/h2>\n

Given, probabilities of speaking truth are<\/p>\n

P(A) = \\(4\\over 5\\) and P(B) = \\(3\\over 4\\)<\/p>\n

And their corresponding probabilities of not speaking truth are<\/p>\n

P(A’) = \\(1\\over 5\\)\u00a0 and P(B’) = \\(1\\over 4\\)<\/p>\n

The probability that they contradict each other<\/p>\n

= P(A).P(B’) + P(B).P(A’)<\/p>\n

= \\(4\\over 5\\) \\(\\times\\) \\(1\\over 4\\) + \\(1\\over 5\\) \\(\\times\\) \\(3\\over 4\\)<\/p>\n

= \\(7\\over 20\\)<\/p>\n

\n

Similar Questions<\/h3>\n

The probability of India winning a test match against the west indies is 1\/2 assuming independence from match to match. The probability that in a match series India\u2019s second win occurs at the third test is<\/a><\/p>\n

A fair die is tossed eight times. The probability that a third six is observed on the eight throw, is<\/a><\/p>\n

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A and B play a game, where each is asked to select a number from 1 to 25. If the two numbers match, both of them win a prize. The probability that they will not win a prize in a single trial is<\/a><\/p>\n

At a telephone enquiry system, the number of phone calls regarding relevant enquiry follow. Poisson distribution with an average of 5 phone calls during 10 min time intervals. The probability that there is almost one phone call during a 10 min time period is<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"

Solution : Given, probabilities of speaking truth are P(A) = \\(4\\over 5\\) and P(B) = \\(3\\over 4\\) And their corresponding probabilities of not speaking truth are P(A’) = \\(1\\over 5\\)\u00a0 and P(B’) = \\(1\\over 4\\) The probability that they contradict each other = P(A).P(B’) + P(B).P(A’) = \\(4\\over 5\\) \\(\\times\\) \\(1\\over 4\\) + \\(1\\over 5\\) …<\/p>\n

The probability that A speaks truth is 4\/5 while this probability for B is 3\/4. The probability that they contradict each other when asked to speak on a fact is<\/span> Read More »<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"default","ast-global-header-display":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"default","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":""},"categories":[43,44],"tags":[],"yoast_head":"\nThe probability that A speaks truth is 4\/5 while this probability for B is 3\/4. The probability that they contradict each other when asked to speak on a fact is<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/mathemerize.com\/the-probability-that-a-speaks-truth-is-4-5-while-this-probability-for-b-is-3-4-the-probability-that-they-contradict-each-other-when-asked-to-speak-on-a-fact-is\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"The probability that A speaks truth is 4\/5 while this probability for B is 3\/4. The probability that they contradict each other when asked to speak on a fact is\" \/>\n<meta property=\"og:description\" content=\"Solution : Given, probabilities of speaking truth are P(A) = (4over 5) and P(B) = (3over 4) And their corresponding probabilities of not speaking truth are P(A’) = (1over 5)\u00a0 and P(B’) = (1over 4) The probability that they contradict each other = P(A).P(B’) + P(B).P(A’) = (4over 5) (times) (1over 4) + (1over 5) … The probability that A speaks truth is 4\/5 while this probability for B is 3\/4. 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