{"id":7011,"date":"2021-10-22T14:46:47","date_gmt":"2021-10-22T09:16:47","guid":{"rendered":"https:\/\/mathemerize.com\/?p=7011"},"modified":"2021-10-25T09:17:26","modified_gmt":"2021-10-25T03:47:26","slug":"the-median-of-a-set-of-9-distinct-observations-is-20-5-if-each-of-the-largest-4-observation-of-the-set-is-increased-by-2-then-the-median-of-the-new-is","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/the-median-of-a-set-of-9-distinct-observations-is-20-5-if-each-of-the-largest-4-observation-of-the-set-is-increased-by-2-then-the-median-of-the-new-is\/","title":{"rendered":"The median of a set of 9 distinct observations is 20.5. If each of the largest 4 observation of the set is increased by 2, then the median of the new is"},"content":{"rendered":"
Median of new set remains the same as of the original set.<\/p>\n
The mean and variance of a random variable X having a binomial distribution are 4 and 2 respectively, then P(X = 1) is<\/a><\/p>\n Let \\(x_1\\), \\(x_2\\), \u2026.. , \\(x_n\\), be n observations such that \\(\\sum{x_i}^2\\) = 400 and \\(\\sum{x_i}\\) = 80. Then, a possible value of among the following is<\/a><\/p>\n The mean and the variance of a binomial distribution are 4 and 2, respectively. Then, the probability of 2 success is<\/a><\/p>\n In a series of 2n observations, half of them equals a and remaining half equal -a. If the standard deviation of the observation is 2, then |a| equal to<\/a><\/p>\n