{"id":7057,"date":"2021-10-22T16:00:03","date_gmt":"2021-10-22T10:30:03","guid":{"rendered":"https:\/\/mathemerize.com\/?p=7057"},"modified":"2021-10-25T09:43:32","modified_gmt":"2021-10-25T04:13:32","slug":"find-the-distance-between-the-line-12x-5y-9-0-and-the-point-21","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/find-the-distance-between-the-line-12x-5y-9-0-and-the-point-21\/","title":{"rendered":"Find the distance between the line 12x – 5y + 9 = 0 and the point (2,1)"},"content":{"rendered":"
We have line 12x – 5y + 9 = 0 and the point (2,1)<\/p>\n
Required distance = |\\(12*2 – 5*1 + 9\\over {\\sqrt{12^2 + (-5)^2}}\\)|<\/p>\n
= \\(|24-5+9|\\over 13\\) = \\(28\\over 13\\)<\/p>\n
If p is the length of the perpendicular from the origin to the line \\(x\\over a\\) + \\(y\\over b\\) = 1, then prove that \\(1\\over p^2\\) = \\(1\\over a^2\\) + \\(1\\over b^2\\)<\/a><\/p>\n If the line 2x + y = k passes through the point which divides the line segment joining the points (1,1) and (2,4) in the ratio 3:2, then k is equal to<\/a><\/p>\n The x-coordinate of the incenter of the triangle that has the coordinates of mid-point of its sides as (0,1), (1,1) and (1,0) is<\/a><\/p>\n Let a, b, c and d be non-zero numbers. If the point of intersection of the lines 4ax+2ay+c=0 and 5bx+2by+d=0 lies in the fourth quadrant and is equidistant from the two axes, then<\/a><\/p>\n