{"id":7194,"date":"2021-10-23T01:05:49","date_gmt":"2021-10-22T19:35:49","guid":{"rendered":"https:\/\/mathemerize.com\/?p=7194"},"modified":"2021-10-25T00:47:09","modified_gmt":"2021-10-24T19:17:09","slug":"find-the-value-of-2log2over-5-3log25over-8-log625over-128","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/find-the-value-of-2log2over-5-3log25over-8-log625over-128\/","title":{"rendered":"Find the value of \\(2log{2\\over 5}\\) + \\(3log{25\\over 8}\\) – \\(log{625\\over 128}\\)."},"content":{"rendered":"

Solution :<\/h2>\n

\\(2log{2\\over 5}\\) + \\(3log{25\\over 8}\\) + \\(log{128\\over 625}\\)<\/p>\n

= \\(log{2^2\\over 5^2}\\) + \\(log({5^2\\over 2^3})^3\\) + \\(log{2^7\\over 5^4}\\)<\/p>\n

= \\(log({2^2\\over 5^2}{5^6\\over 2^9}{2^7\\over 5^4})\\) = log 1 = 0<\/p>\n


\n

Similar Questions<\/h3>\n

Solve for x : \\(2^{x + 2}\\) > \\(({1\\over 4})^{1\\over x}\\).<\/a><\/p>\n

Evaluate the given log : \\(81^{l\\over {log_5 3}}\\) + \\(27^{log_9 36}\\) + \\(3^{4\\over {log_7 9}}\\).<\/a><\/p>\n

If \\(log_a x\\) = p and \\(log_b {x^2}\\) = q then \\(log_x \\sqrt{ab}\\) is equal to<\/a><\/p>\n

If \\(log_e x\\) \u2013 \\(log_e y\\) = a, \\(log_e y\\) \u2013 \\(log_e z\\) = b & \\(log_e z\\) \u2013 \\(log_e x\\) = c, then find the value of \\(({x\\over y})^{b-c}\\) \\(\\times\\) \\(({y\\over z})^{c-a}\\) \\(\\times\\) \\(({z\\over x})^{a-b}\\).<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"

Solution : \\(2log{2\\over 5}\\) + \\(3log{25\\over 8}\\) + \\(log{128\\over 625}\\) = \\(log{2^2\\over 5^2}\\) + \\(log({5^2\\over 2^3})^3\\) + \\(log{2^7\\over 5^4}\\) = \\(log({2^2\\over 5^2}{5^6\\over 2^9}{2^7\\over 5^4})\\) = log 1 = 0 Similar Questions Solve for x : \\(2^{x + 2}\\) > \\(({1\\over 4})^{1\\over x}\\). Evaluate the given log : \\(81^{l\\over {log_5 3}}\\) + \\(27^{log_9 36}\\) + \\(3^{4\\over …<\/p>\n

Find the value of \\(2log{2\\over 5}\\) + \\(3log{25\\over 8}\\) – \\(log{625\\over 128}\\).<\/span> Read More »<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"default","ast-global-header-display":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"default","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":""},"categories":[55,43],"tags":[],"yoast_head":"\nFind the value of \\(2log{2\\over 5}\\) + \\(3log{25\\over 8}\\) - \\(log{625\\over 128}\\).<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/mathemerize.com\/find-the-value-of-2log2over-5-3log25over-8-log625over-128\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Find the value of \\(2log{2\\over 5}\\) + \\(3log{25\\over 8}\\) - \\(log{625\\over 128}\\).\" \/>\n<meta property=\"og:description\" content=\"Solution : (2log{2over 5}) + (3log{25over 8}) + (log{128over 625}) = (log{2^2over 5^2}) + (log({5^2over 2^3})^3) + (log{2^7over 5^4}) = (log({2^2over 5^2}{5^6over 2^9}{2^7over 5^4})) = log 1 = 0 Similar Questions Solve for x : (2^{x + 2}) > (({1over 4})^{1over x}). Evaluate the given log : (81^{lover {log_5 3}}) + (27^{log_9 36}) + (3^{4over … Find the value of (2log{2over 5}) + (3log{25over 8}) – (log{625over 128}). 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