{"id":7205,"date":"2021-10-23T01:36:49","date_gmt":"2021-10-22T20:06:49","guid":{"rendered":"https:\/\/mathemerize.com\/?p=7205"},"modified":"2021-10-25T09:55:07","modified_gmt":"2021-10-25T04:25:07","slug":"find-the-number-of-solutions-of-tanx-secx-2cosx-in-0-2pi","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/find-the-number-of-solutions-of-tanx-secx-2cosx-in-0-2pi\/","title":{"rendered":"Find the number of solutions of tanx + secx = 2cosx in [0, \\(2\\pi\\)]."},"content":{"rendered":"
Here, tanx + secx = 2cosx\u00a0 \u00a0 \u00a0 \u00a0\\(\\implies\\)\u00a0 \u00a0 \u00a0sinx + 1 = \\(2cos^2x\\)<\/p>\n
\\(\\implies\\) \\(2sin^2x\\) + sinx – 1 = 0\u00a0 \u00a0 \u00a0\\(\\implies\\)\u00a0 \u00a0 sinx = \\(1\\over 2\\), -1<\/p>\n
But sinx = -1 \\(\\implies\\) x = \\(3\\pi\\over 2\\) for which tanx + secx = 2cosx\u00a0 is not defined.<\/p>\n
Thus, sinx = \\(1\\over 2\\) \\(\\implies\\) x = \\(\\pi\\over 6\\),\u00a0 \\(5\\pi\\over 6\\)<\/p>\n
\\(\\implies\\)\u00a0 number of solutions of tanx + secx = 2cosx is 2.<\/p>\n
If \\({1\\over 6}sin\\theta\\), \\(cos\\theta\\) and \\(tan\\theta\\) are in G.P. then the general solution for \\(\\theta\\) is<\/a><\/p>\n Solve : cos3x + sin2x \u2013 sin4x = 0<\/a><\/p>\n Solve : 6 \u2013 10cosx = 3\\(sin^2x\\)<\/a><\/p>\n