{"id":7754,"date":"2021-11-06T00:42:32","date_gmt":"2021-11-05T19:12:32","guid":{"rendered":"https:\/\/mathemerize.com\/?p=7754"},"modified":"2021-11-06T01:35:57","modified_gmt":"2021-11-05T20:05:57","slug":"what-is-the-integration-of-sin-inverse-x-whole-square","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/what-is-the-integration-of-sin-inverse-x-whole-square\/","title":{"rendered":"What is the integration of sin inverse x whole square ?"},"content":{"rendered":"
We have, I = \\((sin^{-1}x)^2\\) dx<\/p>\n
Let \\(sin^{-1}x\\) = t, Then, x = sin t \\(\\implies\\) dx = cos t dt<\/p>\n
\\(\\therefore\\) I = \\(\\int\\) \\((sin^{-1}x)^2\\) dx<\/p>\n
I = \\(\\int\\) \\(t^2\\) cos t dt<\/p>\n
Applying integration by parts and,<\/p>\n
Taking \\(t^2\\) as first function and cos t as second function,<\/p>\n
I = \\(t^2\\) (sin t) – \\(\\int\\) (sin t) – \\(\\int\\) 2t sin t dt = \\(t^2\\) sin t – 2 \\(\\int\\) t sin t dt<\/p>\n
Again applying integration by parts and,<\/p>\n
Taking t as first function and sin t as second function,<\/p>\n
I = \\(t^2\\) sin t – 2{ t ( -cos t) – \\(\\int\\) 1 \\(\\times\\) (-cos t) dt }<\/p>\n
I = \\(t^2\\) sin t – 2{ -t cos t + \\(\\int\\) cos t dt }<\/p>\n
I = \\(t^2\\) sin t – 2( -t cos t + sin t ) + C<\/p>\n
I = \\(t^2\\) sin t – 2{ -t \\(\\sqrt{1 – sin^2 t}\\) + sin t } + C<\/p>\n
I = \\(xsin^{-1} x\\) – 2{ – \\(\\sqrt{1 – x^2} sin^{-1}x\\) + x } + C<\/p>\n
What is the integration of sin inverse root x ?<\/a><\/p>\n What is integration of sin inverse cos x ?<\/a><\/p>\n What is the integration of x sin inverse x dx ?<\/a><\/p>\n What is the integration of tan inverse root x ?<\/a><\/p>\n