{"id":7788,"date":"2021-11-06T14:08:46","date_gmt":"2021-11-06T08:38:46","guid":{"rendered":"https:\/\/mathemerize.com\/?p=7788"},"modified":"2021-11-06T15:36:48","modified_gmt":"2021-11-06T10:06:48","slug":"what-is-the-integration-of-sec-inverse-root-x","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/what-is-the-integration-of-sec-inverse-root-x\/","title":{"rendered":"What is the integration of sec inverse root x ?"},"content":{"rendered":"
We have, I = \\(sec^{-1}\\sqrt{x}\\) dx<\/p>\n
Let x = \\(sec^2t\\)<\/p>\n
dx = \\(2sec^2 t tan t\\) dt<\/p>\n
I = t.\\(2sec^2 t tan t\\) dt<\/p>\n
u = t\u00a0 and v = \\(tan^2 t\\)<\/p>\n
I = \\(\\int\\) u.dv = u.v – \\(\\int\\) v.du = \\(t.tan^2 t\\) – \\(\\int\\) \\(tan^2 t\\) dt<\/p>\n
I = \\(t.tan^2 t\\) – \\(\\int\\) \\(sec^2 t – 1\\) dt<\/p>\n
I = \\(t.tan^2 t\\) – \\(\\int\\) \\(sec^2 t\\) + \\(int\\) 1 dt<\/p>\n
I = \\(t.tan^2 t\\) – tan t + t + C = \\(t.sec^2 t\\) – tan t + C<\/p>\n
I = \\(xsec^{-1}\\sqrt{x}\\) – \\(\\sqrt{sec^2t – 1}\\) + C<\/p>\n
I = \\(xsec^{-1}\\sqrt{x}\\) – \\(\\sqrt{x – 1}\\) + C<\/p>\n
What is the integration of cos inverse root x ?<\/a><\/p>\n What is the integration of x cos inverse x ?<\/a><\/p>\n What is integration of sin inverse cos x ?<\/a><\/p>\n What is the integration of sin inverse root x ?<\/a><\/p>\n