{"id":7845,"date":"2021-11-09T14:17:01","date_gmt":"2021-11-09T08:47:01","guid":{"rendered":"https:\/\/mathemerize.com\/?p=7845"},"modified":"2021-11-09T14:44:55","modified_gmt":"2021-11-09T09:14:55","slug":"find-the-equation-of-line-parallel-to-y-axis-and-drawn-through-the-point-of-intersection-of-the-lines-x-7y-5-0-and-3x-y-0","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/find-the-equation-of-line-parallel-to-y-axis-and-drawn-through-the-point-of-intersection-of-the-lines-x-7y-5-0-and-3x-y-0\/","title":{"rendered":"Find the equation of line parallel to y-axis and drawn through the point of intersection of the lines x – 7y + 5 = 0 and 3x + y = 0."},"content":{"rendered":"
On solving the equations x – 7y + 5 = 0 and 3x + y = 0 by using point of intersection formula, we get<\/p>\n
x = \\(-5\\over 22\\) and y = \\(15\\over 22\\)<\/p>\n
So, given lines intersect at \\(({-5\\over 22}., {15\\over 22})\\)<\/p>\n
Let the equation of the required line be<\/p>\n
x = \\(\\lambda\\)\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0……….(i)<\/p>\n
because the equation of a line parallel to y-axis is x = constant.<\/p>\n
Since, equation (i) passes through \\(({-5\\over 22}., {15\\over 22})\\)<\/p>\n
\\(\\therefore\\)\u00a0 \u00a0\\(\\lambda\\) = \\(-5\\over 22\\)<\/p>\n
Substituting the value of \\(\\lambda\\) in equation (i), we get<\/p>\n
x = \\(-5\\over 22\\) or,\u00a0 22x + 5 = 0<\/p>\n
as the equation of the required line.<\/p>\n
Find the coordinates of the point of intersecton of the lines 2x \u2013 y + 3 = 0 and x + y \u2013 5 = 0.<\/a><\/p>\n Find the equation of line joining the point (3, 5) to the point of intersection of the lines 4x + y \u2013 1 = 0 and 7x \u2013 3y \u2013 35 = 0.<\/a><\/p>\n Find the equation of lines which passes through the point (3,4) and the sum of intercepts on the axes is 14.<\/a><\/p>\n