{"id":7911,"date":"2021-11-10T16:53:14","date_gmt":"2021-11-10T11:23:14","guid":{"rendered":"https:\/\/mathemerize.com\/?p=7911"},"modified":"2021-11-10T22:59:04","modified_gmt":"2021-11-10T17:29:04","slug":"what-is-the-integration-of-log-1-x","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/what-is-the-integration-of-log-1-x\/","title":{"rendered":"What is the integration of log 1\/x ?"},"content":{"rendered":"
We have, I = \\(\\int\\) \\(log {1\\over x}\\) dx<\/p>\n
I = \\(\\int\\) \\(log 1 – log x\\) dx = \\(\\int\\) (-log x) dx<\/p>\n
By using integration by parts<\/a> formula,<\/p>\n Let I = -(\\(\\int\\) log x .1) dx<\/p>\n where log x is the first function and 1 is the second function according to ilate rule.<\/p>\n I = – (log x . {\\(\\int\\) 1 dx} – \\(\\int\\) { \\(d\\over dx\\) (log x) . \\(\\int\\) 1 dx }) dx<\/p>\n I = – {(log x) x – \\(\\int\\) \\(1\\over x\\).x }dx\u00a0<\/p>\n = – x (log x) + \\(\\int\\) 1 dx<\/p>\n = – x (log x) + x + C = x – x log x + C<\/p>\n Hence, the integration of\u00a0 log 1\/x with respect to x is x – log x + C<\/p>\n What is the integration of log cos x dx ?<\/a><\/p>\n What is the integration of \\((log x)^2\\) dx ?<\/a><\/p>\n What is the integration of 1\/x log x ?<\/a><\/p>\n
\nSimilar Questions<\/h3>\n