{"id":8060,"date":"2021-11-13T19:34:19","date_gmt":"2021-11-13T14:04:19","guid":{"rendered":"https:\/\/mathemerize.com\/?p=8060"},"modified":"2021-11-14T00:59:10","modified_gmt":"2021-11-13T19:29:10","slug":"the-angle-of-intersection-between-the-curve-x2-32y-and-y2-4x-at-point-16-8-is","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/the-angle-of-intersection-between-the-curve-x2-32y-and-y2-4x-at-point-16-8-is\/","title":{"rendered":"The angle of intersection between the curve \\(x^2\\) = 32y and \\(y^2\\) = 4x at point (16, 8) is"},"content":{"rendered":"
\\(x^2\\) = 32y\u00a0 \\(\\implies\\)\u00a0 \\(dy\\over dx\\) = \\(x\\over 16\\)\u00a0 \\(\\implies\\)\u00a0 \\(y^2\\) = 4x \\(\\implies\\)\u00a0 \\(dy\\over dx\\) = \\(2\\over y\\)<\/p>\n
\\(\\therefore\\)\u00a0 at\u00a0 (16, 8), \\((dy\\over dx)_1\\) = 1, \\((dy\\over dx)_2\\) = \\(1\\over 4\\)<\/p>\n
So, required angle<\/a> = \\(tan^{-1}({1 – {1\\over 4}\\over 1 + 1({1\\over 4})})\\)<\/p>\n = \\(tan^{-1}({3\\over 5})\\)<\/p>\n Find the equations of the tangent and the normal at the point \u2018t\u2019 on the curve x = \\(a sin^3 t\\), y = \\(b cos^3 t\\).<\/a><\/p>\n Find the equation of the normal to the curve y = \\(2x^2 + 3 sin x\\) at x = 0.<\/a><\/p>\n Find the angle between the curves xy = 6 and \\(x^2 y\\) =12.<\/a><\/p>\n Check the orthogonality of the curves \\(y^2\\) = x and \\(x^2\\) = y.<\/a><\/p>\n
\nSimilar Questions<\/h3>\n