{"id":9128,"date":"2021-12-29T17:09:57","date_gmt":"2021-12-29T11:39:57","guid":{"rendered":"https:\/\/mathemerize.com\/?p=9128"},"modified":"2021-12-29T17:22:13","modified_gmt":"2021-12-29T11:52:13","slug":"what-is-the-value-of-cos-45-degrees","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/what-is-the-value-of-cos-45-degrees\/","title":{"rendered":"What is the Value of Cos 45 Degrees ?"},"content":{"rendered":"
The value of cos 45 degrees<\/strong> is \\(1\\over \\sqrt{2}\\)<\/strong>.<\/p>\n Proof :<\/strong><\/p>\n Let ABC be a triangle, right angled at B, in which \\(\\angle\\) A = \\(\\angle\\) C = 45 degrees<\/p>\n \\(\\therefore\\) BC = AB<\/p>\n Let AB = BC = a<\/p>\n Then by pythagoras theorem,<\/p>\n \\(AC^2\\) = \\(AB^2\\) + \\(BC^2\\) = \\(a^2\\) + \\(a^2\\) = \\(2a^2\\)<\/p>\n \\(\\implies\\) AC = \\(\\sqrt{2}a\\)<\/p>\n In \\(\\Delta\\) ABC, \\(\\angle\\) C = 45 degrees<\/p>\n