{"id":9181,"date":"2022-01-01T00:07:55","date_gmt":"2021-12-31T18:37:55","guid":{"rendered":"https:\/\/mathemerize.com\/?p=9181"},"modified":"2022-01-01T00:32:56","modified_gmt":"2021-12-31T19:02:56","slug":"prove-that-cos90-theta-sintheta","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/prove-that-cos90-theta-sintheta\/","title":{"rendered":"Prove that \\(Cos(90 – \\theta)\\) = \\(Sin\\theta\\)."},"content":{"rendered":"
Draw a right angled triangle ABC right angled at B.<\/p>\n
Let \\(\\angle\\) A = \\(\\theta\\), then \\(\\angle\\) C = 90 – \\(\\theta\\)<\/p>\n
sin A = \\(sin\\theta\\) = \\(BC\\over AC\\) ……..(1)<\/p>\n
cos C = \\(cos(90 – \\theta)\\) = \\(BC\\over AC\\) ……..(2)<\/p>\n
From (1) and (2), we have<\/p>\n
\\(cos(90 – \\theta)\\) = \\(sin\\theta\\)<\/p>\n","protected":false},"excerpt":{"rendered":"
Solution : Draw a right angled triangle ABC right angled at B. Let \\(\\angle\\) A = \\(\\theta\\), then \\(\\angle\\) C = 90 – \\(\\theta\\) sin A = \\(sin\\theta\\) = \\(BC\\over AC\\) ……..(1) cos C = \\(cos(90 – \\theta)\\) = \\(BC\\over AC\\) …<\/p>\n