{"id":9200,"date":"2022-01-03T01:59:37","date_gmt":"2022-01-02T20:29:37","guid":{"rendered":"https:\/\/mathemerize.com\/?p=9200"},"modified":"2022-01-03T02:13:01","modified_gmt":"2022-01-02T20:43:01","slug":"prove-that-sin2-theta-cos2-theta-1","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/prove-that-sin2-theta-cos2-theta-1\/","title":{"rendered":"Prove that \\(sin^2 \\theta\\) + \\(cos^2 \\theta\\) = 1."},"content":{"rendered":"

Solution :<\/h2>\n

In right angled triangle ABC,\"\"<\/p>\n

\\(sin \\theta\\) = \\(BC\\over AC\\)  \\(\\implies\\)   \\(sin^2 \\theta\\) = \\(BC^2\\over AC^2\\)<\/p>\n

\\(cos \\theta\\) = \\(AB\\over AC\\)  \\(\\implies\\)   \\(cos^2 \\theta\\) = \\(AB^2\\over AC^2\\)<\/p>\n

On adding,<\/p>\n

\\(sin^2 \\theta\\) + \\(cos^2 \\theta\\) = \\(BC^2\\over AC^2\\) + \\(AB^2\\over AC^2\\)<\/p>\n

\\(sin^2 \\theta\\) + \\(cos^2 \\theta\\) = \\(BC^2 + AB^2\\over AC^2\\) = \\(AC^2\\over AC^2\\) = 1<\/p>\n

[ By Pythagoras theorem,  \\(AC^2\\) = \\(BC^2 + AB^2\\) ]<\/p>\n

\\(\\implies\\) \\(sin^2 \\theta\\) + \\(cos^2 \\theta\\) = 1<\/p>\n","protected":false},"excerpt":{"rendered":"

Solution : In right angled triangle ABC, \\(sin \\theta\\) = \\(BC\\over AC\\)  \\(\\implies\\)   \\(sin^2 \\theta\\) = \\(BC^2\\over AC^2\\) \\(cos \\theta\\) = \\(AB\\over AC\\)  \\(\\implies\\)   \\(cos^2 \\theta\\) = \\(AB^2\\over AC^2\\) On adding, \\(sin^2 \\theta\\) + \\(cos^2 \\theta\\) = \\(BC^2\\over AC^2\\) + \\(AB^2\\over AC^2\\) \\(sin^2 \\theta\\) + \\(cos^2 \\theta\\) = \\(BC^2 + AB^2\\over AC^2\\) = \\(AC^2\\over AC^2\\) …<\/p>\n

Prove that \\(sin^2 \\theta\\) + \\(cos^2 \\theta\\) = 1.<\/span> Read More »<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"default","ast-global-header-display":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":""},"categories":[43,60],"tags":[],"yoast_head":"\nProve that \\(sin^2 \\theta\\) + \\(cos^2 \\theta\\) = 1. - Mathemerize<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/mathemerize.com\/prove-that-sin2-theta-cos2-theta-1\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Prove that \\(sin^2 \\theta\\) + \\(cos^2 \\theta\\) = 1. - Mathemerize\" \/>\n<meta property=\"og:description\" content=\"Solution : In right angled triangle ABC, (sin theta) = (BCover AC)  (implies)   (sin^2 theta) = (BC^2over AC^2) (cos theta) = (ABover AC)  (implies)   (cos^2 theta) = (AB^2over AC^2) On adding, (sin^2 theta) + (cos^2 theta) = (BC^2over AC^2) + (AB^2over AC^2) (sin^2 theta) + (cos^2 theta) = (BC^2 + AB^2over AC^2) = (AC^2over AC^2) … Prove that (sin^2 theta) + (cos^2 theta) = 1. 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Mathemerize","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/mathemerize.com\/prove-that-sin2-theta-cos2-theta-1\/","og_locale":"en_US","og_type":"article","og_title":"Prove that \\(sin^2 \\theta\\) + \\(cos^2 \\theta\\) = 1. - Mathemerize","og_description":"Solution : In right angled triangle ABC, (sin theta) = (BCover AC)  (implies)   (sin^2 theta) = (BC^2over AC^2) (cos theta) = (ABover AC)  (implies)   (cos^2 theta) = (AB^2over AC^2) On adding, (sin^2 theta) + (cos^2 theta) = (BC^2over AC^2) + (AB^2over AC^2) (sin^2 theta) + (cos^2 theta) = (BC^2 + AB^2over AC^2) = (AC^2over AC^2) … Prove that (sin^2 theta) + (cos^2 theta) = 1. 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