The value of sin 15 degrees<\/strong> is \\(\\sqrt{3} – 1\\over 2\\sqrt{2}\\)<\/strong>.<\/p>\n
Proof :<\/strong><\/p>\n
We will write sin 15 as sin (45 – 30).<\/p>\n
By using formula sin (A – B) = sin A cos B – cos A sin B,<\/p>\n
sin (45 – 30) = sin 45 cos 30 – cos 45 sin 30<\/p>\n
\\(\\implies\\) sin 15 = \\(1\\over \\sqrt{2}\\) \\(\\times\\) \\(\\sqrt{3}\\over 2\\) – \\(1\\over \\sqrt{2}\\) \\(\\times\\) \\(1\\over 2\\)<\/p>\n
\\(\\implies\\) sin 15 = \\(\\sqrt{3} – 1\\over 2\\sqrt{2}\\)<\/p>\n","protected":false},"excerpt":{"rendered":"
Solution : The value of sin 15 degrees is \\(\\sqrt{3} – 1\\over 2\\sqrt{2}\\). Proof : We will write sin 15 as sin (45 – 30). By using formula sin (A – B) = sin A cos B – cos A sin B, sin (45 – 30) = sin 45 cos 30 – cos 45 sin …<\/p>\n