{"id":9462,"date":"2022-01-14T15:28:59","date_gmt":"2022-01-14T09:58:59","guid":{"rendered":"https:\/\/mathemerize.com\/?p=9462"},"modified":"2022-01-14T16:23:46","modified_gmt":"2022-01-14T10:53:46","slug":"what-is-the-general-solution-of-tan2-theta-tan2-alpha","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/what-is-the-general-solution-of-tan2-theta-tan2-alpha\/","title":{"rendered":"What is the General Solution of \\(tan^2 \\theta\\) =\\(tan^2 \\alpha\\) ?"},"content":{"rendered":"
The general solution of \\(tan^2 \\theta\\) = \\(tan^2 \\alpha\\)<\/strong> is given by \\(\\theta\\) = \\(n\\pi \\pm \\alpha\\), n \\(\\in\\) Z.<\/strong><\/p>\n Proof :<\/strong><\/p>\n We have, \\(tan^2 \\theta\\) =\\(tan^2 \\alpha\\)<\/p>\n \\(\\implies\\) \\(1 – tan^2\\theta\\over 1 + tan^2 \\theta\\) =\\(1 – tan^2\\alpha\\over 1 + tan^2 \\alpha\\)<\/p>\n \\(\\implies\\) \\(cos 2\\theta\\) = \\(cos 2\\alpha\\)<\/p>\n \\(\\implies\\) \\(2\\theta\\) = \\(2n\\pi \\pm 2\\alpha\\), n \\(\\in\\) Z.<\/p>\n \\(\\implies\\) \\(\\theta\\) = \\(n\\pi \\pm \\alpha\\), n \\(\\in\\) Z.<\/p>\n","protected":false},"excerpt":{"rendered":" Solution : The general solution of \\(tan^2 \\theta\\) = \\(tan^2 \\alpha\\) is given by \\(\\theta\\) = \\(n\\pi \\pm \\alpha\\), n \\(\\in\\) Z. Proof : We have, \\(tan^2 \\theta\\) =\\(tan^2 \\alpha\\) \\(\\implies\\) \\(1 – tan^2\\theta\\over 1 + tan^2 \\theta\\) =\\(1 – tan^2\\alpha\\over 1 + tan^2 \\alpha\\) \\(\\implies\\) \\(cos 2\\theta\\) = \\(cos 2\\alpha\\) \\(\\implies\\) \\(2\\theta\\) = \\(2n\\pi …<\/p>\n