{"id":9892,"date":"2022-01-31T23:16:46","date_gmt":"2022-01-31T17:46:46","guid":{"rendered":"https:\/\/mathemerize.com\/?p=9892"},"modified":"2022-01-31T23:16:47","modified_gmt":"2022-01-31T17:46:47","slug":"radical-axis-of-two-circles","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/radical-axis-of-two-circles\/","title":{"rendered":"Radical Axis of Two circles – Definition and Formula"},"content":{"rendered":"
Here you will learn what is the formula to find the equation of radical axis of two circles.<\/p>\n
Let’s begin –<\/p>\n
Definition<\/strong> : The locus of a point, which moves in such a way that the length of tangents drawn from it to the circle are equal and is called the radical axis.<\/p>\n If two circles are –<\/p>\n \\(S_1\\) = \\(x^2 + y^2 + 2g_1x + 2f_1y + c_1\\) = 0<\/p>\n \\(S_2\\) = \\(x^2 + y^2 + 2g_2x + 2f_2y + c_2\\) = 0<\/p>\n Let P(h, k) is a point and PA, PB are length of two tangents on the circles from point P,<\/p>\n Then from definition –<\/p>\n \\(\\sqrt{h^2 + k^2 + 2g_1h + 2f_1k + c_1}\\) = \\(\\sqrt{h^2 + k^2 + 2g_2h + 2f_2k + c_2}\\)<\/p>\n \\(\\implies\\)\u00a0 \\(2(g_1 – g_2)h + 2(f_1 – f_2)k + c_1 – c_2\\) = 0<\/p>\n \\(\\therefore\\)\u00a0 \u00a0Locus of (h, k)<\/p>\n \\(2x(g_1 – g_2)\\) + \\(2y(f_1 – f_2)\\) + \\(c1 – c_2\\) = 0<\/p>\n \\(S_1 – S_2\\) = 0<\/p><\/blockquote>\n